Solved: Re: Col Cumulative Sum without calling the current row's value

tMinnx · Mar 26, 2024 05:31 AM

Hello, I am quite new to writing JMP scripts and primarily use "Edit Formula" for my work. I have been browsing solutions related to Col Cumulative Sum and could not find one for my specific problem. The simplified version of my data table is as follows.

Row	Week	Col Cumulative Sum	My Wish
1	1	1	0
2	2	3	1
3	3	6	3
4	4	10	6
5	5	15	10
6	6	21	15

The formula below works if the current row value of "Week" is fixed or if I have two separate columns "Week" and "My Wish."

If( Row() != 1,
	Lag( Col Cumulative Sum( :Week ), 1 ),
	0
)

The issue is that the value of the previous row's "Week" is fixed but the current row's is not. And I only have one column "Week" to work with. I am developing a formula that simulates progression based on the previous simulation value. I am simulating the current row's "Week" value based on the previous row's.

Suppose I am working on Row 4 in the column "Week." I want to cumulatively sum all the previous "Week" values without calling the current "Week" value in the function. Otherwise, it creates an illegal reference or cycling problem in my case.

I tried using subscript instead of lag since the lag function calls the current row's "Week" value. It did not work.

If( Row() != 1,
	Col Cumulative Sum( :Week )[Row() - 1],
	0
)

I hope my explanation was clear enough. Thank you for your time and expertise in advance. I use JMP Pro 17.

txnelson · Mar 26, 2024 07:25 AM

Is "Sim Cases" a matrix or a column in a data table?

I do not understand

You appear to be making your solution overly complex.

sim cases = [3,5,2,8];

sum1 = sum(sim cases);
sum2 = sum(([1 1 1 1]*sim cases)[1]);
show(sum1,sum2);

Both sum1 and sum2 provide the same value

sum1 = 18;
sum2 = 18;

I encourage you to read the Discovering JMP document available under the Help pull down menu.

Jim

View solution in original post

txnelson · Mar 27, 2024 6:28 AM

Here is my solution, however, it does not match your solution. I believe your calculations as shown are incorrect for Row 3. See my script, which includes your sample data table.

Names Default To Here( 1 );
dt = New Table( "Example",
	Add Rows( 4 ),
	New Column( "R",
		Numeric,
		"Continuous",
		Set Values( [., 1.4, 1.67, 2.3] )
	),
	New Column( "Cases",
		Expression,
		"None",
		Set Values( {[1, 1, 2, 1], Empty(), Empty(), Empty()} )
	)
);

// The calculation script
casesSum = 0;
For(i=2,i<=nrows(dt),i++,
		Eval( Eval Expr( casesMatrix = Expr( :cases[i - 1] ) ) );
		:R[i] = :R[i] * (1 - (Sum( casesMatrix )+casesSum) * 4 / 100);
		:Cases[i] = casesMatrix * :R[i];
		casesSum = casesSum + sum(casesMatrix);
);


// Row 3 R does not seem to be correct
// I can not come up with .71, I come up with .96192
show(1.4 * (1 - (5 * 4/100)) ); 
show(1.67 * (1 - (10.6 * 4/100)) );

Jim

View solution in original post

jthi · Mar 26, 2024 05:57 AM

You can deduct current weeks value from the cumulative sum

Col Cumulative Sum(:Week) - :Week

-Jarmo

tMinnx · Mar 26, 2024 06:03 AM

The moment I use (:Week) in my formula I get an illegal reference problem. The current row (:Week) has not been fully calculated yet. I can only recall (:Week) from the previous row in theory.

jthi · Mar 26, 2024 06:22 AM

I would use separate columns to avoid all sorts of issues, but I'm not exactly sure what you are trying to achieve as you have full data in your example. Maybe something like this if Col Cumulative Sum doesn't work for you (calculate value using Lag and variable)

If(Row() == 1,
	val = 0,
	val = val + Lag(:Week);
);
val;

-Jarmo

tMinnx · Mar 26, 2024 07:08 AM

Yes, at first, I tried to emulate in the JMP data table what I usually do in Excel spreadsheets by separating columns. I would then call the values of the previous row of a different column. The JMP data table does not behave as Excel spreadsheets, and I am encountering cyclical problems.

So, I keep changing strategies and my current understanding is to keep every required variable in one column to avoid cyclical problems.

txnelson · Mar 26, 2024 06:15 AM

If I am understanding correctly, I think this might be the solution

If( Row() != 1,
	Sum( :Week[Index( 1, Row() - 1 )] ),
	0
)

Jim

tMinnx · Mar 26, 2024 06:56 AM

Thank you for your suggestion on using the Index subscript. I now encounter the issue "object not subscriptable."

My week example was over-simplified and I have a matrix Sim Cases of 4 rows and 1 column in place of week. To transform it into one summarized numerical value, I multiplied the matrix with [1 1 1 1] and added a subscript [1]. It was then followed by the Index subscript.

Sum( ([1 1 1 1] * :Sim Cases)[1][Index( 1, Row() - 1 )] )

I think the resulting numerical value from the original 4x1 matrix is not accepting any subscript after [1]. Or it could be because of the illegal reference (recursion) again.

txnelson · Mar 26, 2024 07:25 AM

Is "Sim Cases" a matrix or a column in a data table?

I do not understand

You appear to be making your solution overly complex.

sim cases = [3,5,2,8];

sum1 = sum(sim cases);
sum2 = sum(([1 1 1 1]*sim cases)[1]);
show(sum1,sum2);

Both sum1 and sum2 provide the same value

sum1 = 18;
sum2 = 18;

I encourage you to read the Discovering JMP document available under the Help pull down menu.

Jim

tMinnx · Mar 26, 2024 4:31 AM

I will keep learning JMP. For now, I will just stick to my Excel spreadsheet. Thanks everyone for your responses.

Sim Cases is a column and I am using Sim Cases of previous rows in creating new rows. So I guess it is both a column and a variable inside that same column.

jthi · Mar 26, 2024 07:36 AM

How JMP tables and spreadsheets behave are totally different and this old post might be a good read JMP is Not a Spreadsheet as it provides some examples and explanation. You can do most of the stuff in JMP but it can take some time to get your head around how columns+rows behave in JMP vs single cell in excel.

-Jarmo