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Mar 18, 2013 8:00 AM
(749 views)

I am trying to do a very simple Power Coefficient Fit in JMP. In excel it is very simple – therefore I know JMP has to be able to do it…but for the life of me I cannot figure it out.... any ideas would be greatly appreciated

Simple Data Set Example:

*Attatched*

Excel fit that I am trying replicate:

1 ACCEPTED SOLUTION

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Solution

You can use the Fit Model platform or Fit Special in the Fit Y by X platform. Fit Special is found under the red triangle in the Fit Y by X report. Choose log transform for both Y and X variables.

A scripting example:

Bivariate**(**

Y**(** :y axis **)**,

X**(** :X axis **)**,

Fit Special**(** xTran**(** "Log" **)**, yTran**(** "Log" **)**, **{**Line Color**(** **{****208**, **64**, **86****}** **)}** **)**

**);**

Results in the equation Log(y axis) = -2,178489 - 0,3877925*Log(X axis),

which is equivalent to y axis=0.1132 x axis^-0.388

2 REPLIES

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You can use the Fit Model platform or Fit Special in the Fit Y by X platform. Fit Special is found under the red triangle in the Fit Y by X report. Choose log transform for both Y and X variables.

A scripting example:

Bivariate**(**

Y**(** :y axis **)**,

X**(** :X axis **)**,

Fit Special**(** xTran**(** "Log" **)**, yTran**(** "Log" **)**, **{**Line Color**(** **{****208**, **64**, **86****}** **)}** **)**

**);**

Results in the equation Log(y axis) = -2,178489 - 0,3877925*Log(X axis),

which is equivalent to y axis=0.1132 x axis^-0.388

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Mar 18, 2013 11:33 AM
(609 views)

Thanks MS, thank worked perfectly... you have no idea how long I was looking for that....