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    <title>topic Re: 一组数据的正态性检验的PValue如何求？ in Discussions</title>
    <link>https://community.jmp.com/t5/Discussions/%E4%B8%80%E7%BB%84%E6%95%B0%E6%8D%AE%E7%9A%84%E6%AD%A3%E6%80%81%E6%80%A7%E6%A3%80%E9%AA%8C%E7%9A%84PValue%E5%A6%82%E4%BD%95%E6%B1%82/m-p/607685#M80932</link>
    <description>&lt;P&gt;&amp;nbsp;Amazing! 谢谢您的解答！！！&lt;/P&gt;</description>
    <pubDate>Fri, 03 Mar 2023 00:23:59 GMT</pubDate>
    <dc:creator>lehaofeng</dc:creator>
    <dc:date>2023-03-03T00:23:59Z</dc:date>
    <item>
      <title>一组数据的正态性检验的PValue如何求？</title>
      <link>https://community.jmp.com/t5/Discussions/%E4%B8%80%E7%BB%84%E6%95%B0%E6%8D%AE%E7%9A%84%E6%AD%A3%E6%80%81%E6%80%A7%E6%A3%80%E9%AA%8C%E7%9A%84PValue%E5%A6%82%E4%BD%95%E6%B1%82/m-p/607031#M80881</link>
      <description>&lt;P&gt;我有一个表，有2000多行，每行数据都要检验正态性，把PValue放到每行数据的最后，请问有公式吗？&lt;/P&gt;</description>
      <pubDate>Fri, 09 Jun 2023 16:05:48 GMT</pubDate>
      <guid>https://community.jmp.com/t5/Discussions/%E4%B8%80%E7%BB%84%E6%95%B0%E6%8D%AE%E7%9A%84%E6%AD%A3%E6%80%81%E6%80%A7%E6%A3%80%E9%AA%8C%E7%9A%84PValue%E5%A6%82%E4%BD%95%E6%B1%82/m-p/607031#M80881</guid>
      <dc:creator>lehaofeng</dc:creator>
      <dc:date>2023-06-09T16:05:48Z</dc:date>
    </item>
    <item>
      <title>Re: 一组数据的正态性检验的PValue如何求？</title>
      <link>https://community.jmp.com/t5/Discussions/%E4%B8%80%E7%BB%84%E6%95%B0%E6%8D%AE%E7%9A%84%E6%AD%A3%E6%80%81%E6%80%A7%E6%A3%80%E9%AA%8C%E7%9A%84PValue%E5%A6%82%E4%BD%95%E6%B1%82/m-p/607078#M80887</link>
      <description>&lt;P&gt;Create the new column in your data table.&amp;nbsp; Make sure you go into the Col Info, and set the format for the column to "PValue".&lt;/P&gt;
&lt;P&gt;Then open the Formula Editor for the new column and paste the below column into it&lt;/P&gt;
&lt;PRE&gt;&lt;CODE class=" language-jsl"&gt;dt = Current Data Table();
// change the Index value for the starting column number of the columns to be analyzed
theRow = dt[Row(), Index( 5, N Col( dt ) - 1 )];
// Create a temporary working data table to calculate the normality on
dtTemp = New Table( "temp", private, New Column( "x", values( theRow ) ) );
// Run the Distribution Platform to calculate the normality
dis = Distribution( invisible, Continuous Distribution( Column( :x ), Fit Normal( Goodness of Fit( 1 ) ) ) );
// Retrieve the P Value of the Normality statistic
pval = (Report( dis )["Goodness-of-Fit Test", Number Col Box( 2 )] &amp;lt;&amp;lt; get)[1];
// Clean up the behind the scenes working table and display
dis &amp;lt;&amp;lt; close window;
Close( dtTemp, nosave );
// Apply the pvalue to the current row
pval;&lt;/CODE&gt;&lt;/PRE&gt;
&lt;P&gt;This formula will take several minutes to run on a 2000 row table.&lt;/P&gt;
&lt;P&gt;The comments in the above formula will not be saved as part of the formula(it;s a JMP efficiency, to keep only the executable part of the formula).&lt;/P&gt;
&lt;P&gt;Normally, JMP data is formatted 90 degrees from the way your data are structured.&amp;nbsp; The column contain the data to be analyzed, and the rows represent the different instances for the given measurment.&lt;/P&gt;</description>
      <pubDate>Thu, 02 Mar 2023 08:18:35 GMT</pubDate>
      <guid>https://community.jmp.com/t5/Discussions/%E4%B8%80%E7%BB%84%E6%95%B0%E6%8D%AE%E7%9A%84%E6%AD%A3%E6%80%81%E6%80%A7%E6%A3%80%E9%AA%8C%E7%9A%84PValue%E5%A6%82%E4%BD%95%E6%B1%82/m-p/607078#M80887</guid>
      <dc:creator>txnelson</dc:creator>
      <dc:date>2023-03-02T08:18:35Z</dc:date>
    </item>
    <item>
      <title>Re: 一组数据的正态性检验的PValue如何求？</title>
      <link>https://community.jmp.com/t5/Discussions/%E4%B8%80%E7%BB%84%E6%95%B0%E6%8D%AE%E7%9A%84%E6%AD%A3%E6%80%81%E6%80%A7%E6%A3%80%E9%AA%8C%E7%9A%84PValue%E5%A6%82%E4%BD%95%E6%B1%82/m-p/607685#M80932</link>
      <description>&lt;P&gt;&amp;nbsp;Amazing! 谢谢您的解答！！！&lt;/P&gt;</description>
      <pubDate>Fri, 03 Mar 2023 00:23:59 GMT</pubDate>
      <guid>https://community.jmp.com/t5/Discussions/%E4%B8%80%E7%BB%84%E6%95%B0%E6%8D%AE%E7%9A%84%E6%AD%A3%E6%80%81%E6%80%A7%E6%A3%80%E9%AA%8C%E7%9A%84PValue%E5%A6%82%E4%BD%95%E6%B1%82/m-p/607685#M80932</guid>
      <dc:creator>lehaofeng</dc:creator>
      <dc:date>2023-03-03T00:23:59Z</dc:date>
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