topic Re: Jump out of a function? in Discussions

Jump out of a function?

pmroz — Wed, 02 Jan 2013 19:29:23 GMT

Is there a way to cleanly jump out of a function? Something like the break() function in a for loop. I've tried throw() but that stops the entire JSL script.

Re: Jump out of a function?

ms — Wed, 02 Jan 2013 21:19:23 GMT

I often enclose error prone expressions in Try() without Throw(). The placement of Try() – within the function or "around" the function call – depends if I only want to escape parts of the function or escape it completely in case of an exception. Throw() halts execution and I tend to use it mainly for debugging.

Compare these examples and their output:

//Try() inside the function escapes chosen parts of function, script execution continues.

exsqr = Function( {x},

x2 = Try( x * x, "Error, move on!" );

Show( "Show this even if x is NaN" );

x2;

);

sq = exsqr( "q" );

Show( sq, "function escape failed, but script continued" );

//Try() enclosing the function call escapes function, script execution continues.

exsqr = Function( {x},

x2 = x * x;

Show( "Don't show this if x is NaN" );

x2;

);

sq = Try( exsqr( "q" ) );

Show( sq, "function escape succeeded!" );

//Try() with Throw() escapes function and script.

exsqr = Function( {x},

x2 = Try( x * x, Throw( "Error, stop here!: " || Char( exception_msg ) ) );

Show( "Don't show this if x is NaN" );

);

sq = exsqr( "q" );

Show( sq, "script stopped!" );

Re: Jump out of a function?

andrewtkarl — Sat, 25 Jul 2020 21:29:30 GMT

Could you use return()?

Re: Jump out of a function?

txnelson — Sat, 25 Jul 2020 23:28:26 GMT

Yes, return() will break out of a function

Re: Jump out of a function?

bswedlove — Thu, 19 Sep 2024 21:34:43 GMT

I am getting an error when trying to exit a function with return().

I get the error when I make a button box

bb = Button Box("SpecsAuto")

then attach a function

bb << Set Function( Return() )

then click the box.

Here is demo code to reproduce the error:

nw = New Window("Win1");
nw << Append(bb = Button Box("SpecsAuto"));
bb << Set Function(
	Print("A");
	Return();
	Print("B");
);
bb << Click();

Re: Jump out of a function?

hogi — Fri, 20 Sep 2024 05:48:45 GMT

set function() also works if no function is provided - like in your script.

To use the magic of return(), you have to put it inside a function:

nw = New Window("Win1");
nw << Append(bb = Button Box("SpecsAuto"));
bb << Set function(Function({},
	Print("A");
	Return();
	Print("B");)
);
bb << Click();