topic Re: Convert decimal to Binary in Discussions

Convert decimal to Binary

justvince — Fri, 04 May 2012 22:37:10 GMT

I need to convert Columns of data (decimal) to binary (8 bit) , then concantenate say the 4 LSB to the next column of data with the 4 MSB. Is there a way to at least convert decimal data to binary in JMP?

Re: Convert decimal to Binary

Sat, 12 May 2012 20:48:09 GMT

Hi - can you adapt the following to do what you need?

// Function to convert an integer into any positive base up to hexadecimal;

base = Function( {n, nbase}, {default local},

ndash = "";

digits= "0123456789ABCDEF";

While( n > 0,

remainder= Mod( n, nbase );

newdigit= Substr( digits, (1 + remainder), 1 );

ndash= newdigit || ndash;

n= (n - remainder)/ nbase;

);

ndash;

);

// Print out a few numbers to show it working in binary;

For( i = 1, i <= 32, i++, Show( Char( i ) || " = " || base( i, 2 ) ) );

// Or create some new columns in a data table and fill them;

dt = New Table( "Number Bases", New Column( "N", numeric, values( Index( 1, 32 ) ) ) );

numberbase = {2, 3, 8, 10, 12, 16}; // Some familiar number bases;

For( i = 1, i <= N Items( numberbase ), i++,

k= numberbase[i];

dt<< New Column( "Base "|| Char( k ), character );

For( j = 1, j <= N Row( dt ), j++,

Column( dt, ("Base "|| Char( k )) )[j] = base( j, k ) );

);

// End of program;

Re: Convert decimal to Binary

justvince — Mon, 14 May 2012 16:36:03 GMT

It is a start. But it appears the function base will not convert a zero to binary 0,

Re: Convert decimal to Binary

Tue, 15 May 2012 07:48:16 GMT

No problem - an extra "if" clause will treat n=0 as a special case:

base = function({n, base}, {default local}, ndash = ""; digits = "0123456789ABCDEF";

if(n > 0, while(n > 0, remainder = mod(n, base); newdigit = substr(digits, (1 + remainder), 1);

ndash = newdigit || ndash; n = (n - remainder) / base), ndash = "0"); ndash);

(I'm assuming that n is a non-negative integer, and that base is a positive integer.)

Re: Convert decimal to Binary

Duane_Hayes — Fri, 26 Jan 2018 17:30:19 GMT

As previously stated:

Hi - can you adapt the following to do what you need?

// Function to convert an integer into any positive base up to hexadecimal;
base = Function( {n, nbase}, {default local},
       ndash = "";
       digits= "0123456789ABCDEF";
     While( n > 0,
              remainder= Mod( n, nbase );
              newdigit= Substr( digits, (1 + remainder), 1 );
              ndash= newdigit || ndash;
              n= (n - remainder)/ nbase;
       );
ndash;
);
 
// Print out a few numbers to show it working in binary;
 
For( i = 1, i <= 32, i++, Show( Char( i ) || " = " || base( i, 2 ) ) );
 
// Or create some new columns in a data table and fill them;
 
dt = New Table( "Number Bases", New Column( "N", numeric, values( Index( 1, 32 ) ) ) );
 
numberbase = {2, 3, 8, 10, 12, 16}; // Some familiar number bases;
 
For( i = 1, i <= N Items( numberbase ), i++,
     k= numberbase[i];
     dt<< New Column( "Base "|| Char( k ), character );
     For( j = 1, j <= N Row( dt ), j++,
     Column( dt, ("Base "|| Char( k )) )[j] = base( j, k ) );
     );
 
// End of program;

And:

No problem - an extra "if" clause will treat n=0 as a special case:

base = function({n, base}, {default local}, ndash = ""; digits = "0123456789ABCDEF";
if(n > 0, while(n > 0, remainder = mod(n, base); newdigit = substr(digits, (1 + remainder), 1);
ndash = newdigit || ndash; n = (n - remainder) / base), ndash = "0"); ndash);

(I'm assuming that n is a non-negative integer, and that base is a positive integer.)