<?xml version="1.0" encoding="UTF-8"?>
<rss xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns:taxo="http://purl.org/rss/1.0/modules/taxonomy/" version="2.0">
  <channel>
    <title>topic Re: Is there an inverse to the Day Of Year() function? in Discussions</title>
    <link>https://community.jmp.com/t5/Discussions/Is-there-an-inverse-to-the-Day-Of-Year-function/m-p/19831#M18076</link>
    <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;P&gt;I assume you have a year column as well.&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;If so, you just need to multiply your Day of Year column by the number of seconds in a day (the &lt;A href="http://www.jmp.com/support/help/Date_Time_Functions.shtml" rel="noopener noreferrer" target="_blank"&gt;In Days(1)&lt;/A&gt; function will give you this) and add it to the value for December 31 of the previous year. It sounds worse in prose than it really is.&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;:Day of Year * In Days(1) + Date DMY(31, 12, :Year - 1)&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="12394_JMPScreenSnapz027.png" style="width: 541px;"&gt;&lt;img src="https://community.jmp.com/t5/image/serverpage/image-id/3568i91464C4E8B7FB72D/image-size/medium?v=v2&amp;amp;px=400" role="button" title="12394_JMPScreenSnapz027.png" alt="12394_JMPScreenSnapz027.png" /&gt;&lt;/span&gt;&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="12404_JMPScreenSnapz028.png" style="width: 375px;"&gt;&lt;img src="https://community.jmp.com/t5/image/serverpage/image-id/3569i6636DAAA50B140D0/image-size/medium?v=v2&amp;amp;px=400" role="button" title="12404_JMPScreenSnapz028.png" alt="12404_JMPScreenSnapz028.png" /&gt;&lt;/span&gt;&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;-Jeff&lt;/P&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
    <pubDate>Wed, 19 Oct 2016 03:44:29 GMT</pubDate>
    <dc:creator>Jeff_Perkinson</dc:creator>
    <dc:date>2016-10-19T03:44:29Z</dc:date>
    <item>
      <title>Is there an inverse to the Day Of Year() function?</title>
      <link>https://community.jmp.com/t5/Discussions/Is-there-an-inverse-to-the-Day-Of-Year-function/m-p/19830#M18075</link>
      <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;P&gt;I have a day of year column, and need to convert it to a date. I've wracked my brain over this. There's probably a simple solution but it escapes me.&lt;/P&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
      <pubDate>Wed, 10 Aug 2016 15:31:34 GMT</pubDate>
      <guid>https://community.jmp.com/t5/Discussions/Is-there-an-inverse-to-the-Day-Of-Year-function/m-p/19830#M18075</guid>
      <dc:creator>mwechtal</dc:creator>
      <dc:date>2016-08-10T15:31:34Z</dc:date>
    </item>
    <item>
      <title>Re: Is there an inverse to the Day Of Year() function?</title>
      <link>https://community.jmp.com/t5/Discussions/Is-there-an-inverse-to-the-Day-Of-Year-function/m-p/19831#M18076</link>
      <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;P&gt;I assume you have a year column as well.&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;If so, you just need to multiply your Day of Year column by the number of seconds in a day (the &lt;A href="http://www.jmp.com/support/help/Date_Time_Functions.shtml" rel="noopener noreferrer" target="_blank"&gt;In Days(1)&lt;/A&gt; function will give you this) and add it to the value for December 31 of the previous year. It sounds worse in prose than it really is.&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;:Day of Year * In Days(1) + Date DMY(31, 12, :Year - 1)&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="12394_JMPScreenSnapz027.png" style="width: 541px;"&gt;&lt;img src="https://community.jmp.com/t5/image/serverpage/image-id/3568i91464C4E8B7FB72D/image-size/medium?v=v2&amp;amp;px=400" role="button" title="12394_JMPScreenSnapz027.png" alt="12394_JMPScreenSnapz027.png" /&gt;&lt;/span&gt;&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;&lt;span class="lia-inline-image-display-wrapper lia-image-align-inline" image-alt="12404_JMPScreenSnapz028.png" style="width: 375px;"&gt;&lt;img src="https://community.jmp.com/t5/image/serverpage/image-id/3569i6636DAAA50B140D0/image-size/medium?v=v2&amp;amp;px=400" role="button" title="12404_JMPScreenSnapz028.png" alt="12404_JMPScreenSnapz028.png" /&gt;&lt;/span&gt;&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;-Jeff&lt;/P&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
      <pubDate>Wed, 19 Oct 2016 03:44:29 GMT</pubDate>
      <guid>https://community.jmp.com/t5/Discussions/Is-there-an-inverse-to-the-Day-Of-Year-function/m-p/19831#M18076</guid>
      <dc:creator>Jeff_Perkinson</dc:creator>
      <dc:date>2016-10-19T03:44:29Z</dc:date>
    </item>
    <item>
      <title>Re: Is there an inverse to the Day Of Year() function?</title>
      <link>https://community.jmp.com/t5/Discussions/Is-there-an-inverse-to-the-Day-Of-Year-function/m-p/19832#M18077</link>
      <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;P&gt;Perfect! The data is all this year so far, so I don't need the year column yet.&lt;/P&gt;&lt;P&gt;Thanks! Yes that was simpler than I thought. I was getting frustrated, and I nearly did in in {shudder} Excel, but then I would have had to copy it back and forth every few days.&lt;/P&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
      <pubDate>Wed, 10 Aug 2016 16:01:22 GMT</pubDate>
      <guid>https://community.jmp.com/t5/Discussions/Is-there-an-inverse-to-the-Day-Of-Year-function/m-p/19832#M18077</guid>
      <dc:creator>mwechtal</dc:creator>
      <dc:date>2016-08-10T16:01:22Z</dc:date>
    </item>
  </channel>
</rss>

