topic Re: Reliability calculation with only failure in Discussions https://community.jmp.com/t5/Discussions/Reliability-calculation-with-only-failure/m-p/18487#M16840 <HTML><HEAD></HEAD><BODY><P>With only one observed failure, you cannot estimate two model parameters (such as alpha and beta for Weibull). You can perform a WeiBayes analysis if you only need to estimate one of these parameters. Select Weibull as the distribution model at the top in Compare Distributions. Then click the red triangle next to the Parametric Estimate - Weibull for the model results and select Fix Parameter. A new section opens where you can enter the known value and then estimate the other.</P><P></P><P>Note that you can estimate the independent parameter but you cannot evaluate goodness of fit with only a single observation.</P></BODY></HTML> Fri, 13 May 2016 21:04:49 GMT Mark_Bailey 2016-05-13T21:04:49Z Reliability calculation with only failure https://community.jmp.com/t5/Discussions/Reliability-calculation-with-only-failure/m-p/18486#M16839 <HTML><HEAD></HEAD><BODY><P><SPAN style="color: #000000; font-family: verdana, geneva, lucida, 'lucida grande', arial, helvetica, sans-serif; font-size: 13.3333px; background-color: #f5f5ff;">Hi,<BR /></SPAN></P><P><SPAN style="color: #000000; font-family: verdana, geneva, lucida, 'lucida grande', arial, helvetica, sans-serif; font-size: 13.3333px; background-color: #f5f5ff;"><BR /></SPAN></P><P><SPAN style="color: #000000; font-family: verdana, geneva, lucida, 'lucida grande', arial, helvetica, sans-serif; font-size: 13.3333px; background-color: #f5f5ff;">I have the following test data </SPAN></P><P></P><P><SPAN style="color: #000000; font-family: verdana, geneva, lucida, 'lucida grande', arial, helvetica, sans-serif; font-size: 13.3333px; background-color: #f5f5ff;">Nr of hours&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; test results</SPAN></P><P></P><P><SPAN style="color: #000000; font-family: verdana, geneva, lucida, 'lucida grande', arial, helvetica, sans-serif; font-size: 13.3333px; background-color: #f5f5ff;">2400&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; not failed, test stopped</SPAN></P><P><SPAN style="color: #000000; font-family: verdana, geneva, lucida, 'lucida grande', arial, helvetica, sans-serif; font-size: 13.3333px; background-color: #f5f5ff;">2400&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; not failed, test stopped</SPAN></P><P><SPAN style="color: #000000; font-family: verdana, geneva, lucida, 'lucida grande', arial, helvetica, sans-serif; font-size: 13.3333px; background-color: #f5f5ff;">2400&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; not failed, test stopped</SPAN></P><P><SPAN style="color: #000000; font-family: verdana, geneva, lucida, 'lucida grande', arial, helvetica, sans-serif; font-size: 13.3333px; background-color: #f5f5ff;">2600&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; failed</SPAN></P><P></P><P><SPAN style="color: #000000; font-family: verdana, geneva, lucida, 'lucida grande', arial, helvetica, sans-serif; font-size: 13.3333px; background-color: #f5f5ff;">I tried to use the 'life distribution' but i dont get any result as i have one failure so i want to know how to to calculate reliability at 750 hours?</SPAN></P><P><SPAN style="color: #000000; font-family: verdana, geneva, lucida, 'lucida grande', arial, helvetica, sans-serif; font-size: 13.3333px; background-color: #f5f5ff;"><BR /></SPAN></P><P><SPAN style="color: #000000; font-family: verdana, geneva, lucida, 'lucida grande', arial, helvetica, sans-serif; font-size: 13.3333px; background-color: #f5f5ff;">BR,</SPAN></P><P><SPAN style="color: #000000; font-family: verdana, geneva, lucida, 'lucida grande', arial, helvetica, sans-serif; font-size: 13.3333px; background-color: #f5f5ff;"><BR /></SPAN></P><P><SPAN style="color: #000000; font-family: verdana, geneva, lucida, 'lucida grande', arial, helvetica, sans-serif; font-size: 13.3333px; background-color: #f5f5ff;">/Tahir<BR /></SPAN></P></BODY></HTML> Fri, 13 May 2016 08:53:36 GMT https://community.jmp.com/t5/Discussions/Reliability-calculation-with-only-failure/m-p/18486#M16839 tahir 2016-05-13T08:53:36Z Re: Reliability calculation with only failure https://community.jmp.com/t5/Discussions/Reliability-calculation-with-only-failure/m-p/18487#M16840 <HTML><HEAD></HEAD><BODY><P>With only one observed failure, you cannot estimate two model parameters (such as alpha and beta for Weibull). You can perform a WeiBayes analysis if you only need to estimate one of these parameters. Select Weibull as the distribution model at the top in Compare Distributions. Then click the red triangle next to the Parametric Estimate - Weibull for the model results and select Fix Parameter. A new section opens where you can enter the known value and then estimate the other.</P><P></P><P>Note that you can estimate the independent parameter but you cannot evaluate goodness of fit with only a single observation.</P></BODY></HTML> Fri, 13 May 2016 21:04:49 GMT https://community.jmp.com/t5/Discussions/Reliability-calculation-with-only-failure/m-p/18487#M16840 Mark_Bailey 2016-05-13T21:04:49Z