topic Re: JSL to change color of specific cause in Pareto Plot in Discussions

JSL to change color of specific cause in Pareto Plot

snagpal — Mon, 14 Mar 2016 23:11:22 GMT

Hello,

I'm trying to change the color of a specific cause in the Pareto Plot using JSL. How can I select a cause by name?

For example, I want to implement something like this:

cause ({"PASS"}) << Colors (Green);

This gives me an error and wants me to use Cause where n is the index of the failure pareto. My issue is that I won't know if my PASS pareto will be #1, #2, etc.

Any suggestions?

Here is my code below:

dt << Pareto Plot(

Cause( :BinName),

Colors (Red),

SendToReport(

Dispatch( {}, "Pareto Plot", OutlineBox, {Set Title( "Pareto of " || (dt << Get Name) )} ),

Dispatch( {"Plots"}, "102", ScaleBox, {Label Row( Show Major Grid( 1 ) )} )

)

Shin

Re: JSL to change color of specific cause in Pareto Plot

Wendy_Murphrey — Thu, 17 Mar 2016 19:53:51 GMT

Hi, Shin.

The following example demonstrates how you can determine the index and color a specific cause by name:

Names Default To Here( 1 );

dt = Open( "$SAMPLE_DATA/Quality Control/Failure Raw Data.jmp" );

/* Obtain the sorted frequency */

dtSumm = dt << Summary( Group( :failure ), private );

dtSumm << Sort( By( :N Rows ), Order( Descending ), Replace Table );

/* Obtain the row number for the desired cause specified by name */

r = (dtSumm << Get Rows Where( :Failure == "oxide defect" ))[1];

/* Generate the Pareto Plot */

pPlot = dt << Pareto Plot(

Cause( :Failure ),

Colors( "Red" ),

/* Set the color for the desired cause */

Cause[r] << Colors( "Green" ),

SendToReport(

Dispatch(

{},

"Pareto Plot",

OutlineBox,

{Set Title( "Pareto of " || (dt << Get Name) )}

Dispatch( {"Plots"}, "102", ScaleBox, {Label Row( Show Major Grid( 1 ) )} )

)

);

I hope this helps.

Wendy

Re: JSL to change color of specific cause in Pareto Plot

snagpal — Mon, 21 Mar 2016 05:13:19 GMT

Hi Wendy,

That was perfect. Thanks for the solution.

Shin