topic Re: JMP 16 to JMP 18- get Legend Server/Item question in Discussions

JMP 16 to JMP 18- get Legend Server/Item question

Neo — Thu, 13 Mar 2025 15:20:50 GMT

I recently moved from JMP 16 to JMP 18 and the following line in my script is causing an error while plotting using the graph builder

server = gb_obj<< Get Legend Server; For Each({item}, server << Get Legend Items, 	item << Set Properties({Marker("Minus")}));

where gb_obj is the graph builder object and error is

Send Expects Scriptable Object at row 6 in access or evaluation of 'List' , {/*###*/LegendModelItem( Label( "meas_para_name" ), Type( "Marker" ) )}

where "meas_para_name" is the name of a measured parameter in the data table plotted.

What to change to get this to work on JMP18?

(let me know if above info is not enough)

Re: JMP 16 to JMP 18- get Legend Server/Item question

hogi — Thu, 13 Mar 2025 21:09:31 GMT

workaround: use get legend item() for each item.

[fixed in JMP19]

Re: JMP 16 to JMP 18- get Legend Server/Item question

Neo — Fri, 14 Mar 2025 10:19:10 GMT

@hogi Thanks. Below (with for each) does not work in JMP 18. What am I missing?

server = gb_expr_obj<< Get Legend Server; For Each({item}, server << Get Legend Item (), 	item << Set Properties({Marker("Minus")}));

Re: JMP 16 to JMP 18- get Legend Server/Item question

hogi — Fri, 14 Mar 2025 13:35:55 GMT

Use Get legend Items in a first step. And use "i" as index for the second step:

server = gb << Get Legend Server;
Nitems = Nitems(( server << Get Legend Items)[1]);
for(i=1, i<= Nitems, i++, 
Eval(Eval Expr(item = server  << Get Legend Item(1, Expr(i))));
	item << Set Label( "Item " || Char( i ) )
);

If you have multiple layers, you might need to change the first index as well.

Re: JMP 16 to JMP 18- get Legend Server/Item question

Neo — Thu, 20 Mar 2025 14:25:52 GMT

@hogi When is JMP 19 getting released?

Re: JMP 16 to JMP 18- get Legend Server/Item question

hogi — Thu, 20 Mar 2025 15:45:31 GMT

2025-09